Answer:
a = 2 ± 2[tex]\sqrt{2}[/tex]
Step-by-step explanation:
a = 1
b = -4
c = -4
x = (-b ± [tex]\sqrt{b^2 - 4ac}[/tex]) / 2a
x = (-(-4) ± [tex]\sqrt{(-4)^2-4(1)(-4)}[/tex]) / 2(1)
x = (4 ± [tex]\sqrt{16 +16}[/tex]) / 2
x = (4 ± 4[tex]\sqrt{2}[/tex]) / 2
x = 2 ± 2[tex]\sqrt{2}[/tex]
Your variable being solved is a so a = 2 ± 2[tex]\sqrt{2}[/tex]
