Answer:
• let the upper row be y and lower row be x
• Considering (4, 82):
[tex]{ \rm{x :y = 4 :82 }} \\ \\ { \rm{ \frac{x}{y} = \frac{4}{82} }} \\ \\{ \boxed { \rm{ \: x = \frac{4y}{82} \: }}}[/tex]
• when y is 22:
[tex]{ \rm{x = \frac{(4 \times 22)}{82} }} \\ \\ { \rm{x \approx1}}[/tex]
Answer: It'd be 1
