aungkhantp48
aungkhantp48 aungkhantp48
  • 19-09-2021
  • Mathematics
contestada

Given that x

2+2kx+4k-3 = 0 has no real roots, show that k satisfies k
2
-4k+3 < 0

Respuesta :

Аноним Аноним
  • 19-09-2021

Answer:

[tex]{ \tt{2 + 2kx + 4k - 3 = 0}} \\ \\ { \tt{0 {x}^{2} + 2kx + (4k - 1) = 0 }}[/tex]

for unreal roots: b² < 4ac

• b is 2k

• a is 0

• c is 4k - 1

[tex]{ \tt{ {(2k)}^{2} < (4 \times 0 \times 4k - 1)}} \\ \\ { \tt{4 {k}^{2} < 0 }} \\ \\ { \boxed{ \tt{k < 0}}}[/tex]

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