laitrang190401 laitrang190401
  • 18-09-2021
  • Mathematics
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[tex](x-1).\sqrt{x^2-4}[/tex]

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Аноним Аноним
  • 18-09-2021

Answer:

[tex] \dashrightarrow \: { \tt{(x - 1) \sqrt{( {x}^{2} - 4) } }} \\ \\ \dashrightarrow \: { \tt{(x - 1) \sqrt{( {x}^{2} - {2}^{2} )} }}[/tex]

• from difference of two squares quadratic law:

[tex]{ \boxed{ \rm{( {a}^{2} - {b}^{2} ) = (a - b)(a + b) }}}[/tex]

• a is x and b is 2

[tex] \dashrightarrow \: { \tt{(x - 1) \sqrt{(x - 2)(x + 2)} }} \\ \\ [/tex]

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