Respuesta :

discipulus

Answer:

[tex]let \: w \: be \: the \: width \: and \: l = 2w \\ area \: = 128 = (w)(2w) \\ 2{w}^{2} = 128 \\ {w}^{2} = 64 \\ w = 8 \: yd \\ l = 16 \\ perimeter \: = 2(8) + 2(16) = 48 \: yd[/tex]

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