kiyondinewton02
kiyondinewton02 kiyondinewton02
  • 19-08-2021
  • Mathematics
contestada

solve the equation 3 cos 2 theta + sin theta = 1 for values of theta from 0 degrees to 180 degrees​

Respuesta :

Trancescient
Trancescient Trancescient
  • 19-08-2021

Step-by-step explanation:

Recall that

[tex]\cos{2\theta} = 1 -2\sin^2\theta[/tex]

so we can write our original equation as

[tex]3 - 6\sin^2{\theta} + \sin{\theta} = 1[/tex] or

[tex]6\sin^2{\theta} - \sin{\theta} - 2 =0[/tex]

Let [tex]x = \sin{\theta}[/tex] so our equation becomes

[tex]6x^2 - x - 2= 0[/tex]

which gives us two roots: [tex]x = -\frac{1}{2}[/tex] and [tex]x = \frac{2}{3}[/tex].

This is equivalent to [tex]\theta = 150°[/tex] and [tex]\theta = 41.8°[/tex]

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