Answer:
23
Step-by-step explanation:
We are given that
f(2)=13
[tex]f'(x)\geq 2[/tex]
[tex]2\leq x\leq 7[/tex]
We have to find the possible small value of f(7).
We know that
[tex]f'(x)=\frac{f(b)-f(a)}{b-a}[/tex]
Using the formula
[tex]f'(x)=\frac{f(7)-f(2)}{7-2}[/tex]
[tex]f'(x)=\frac{f(7)-13}{5}[/tex]
We have
[tex]f'(x)\geq 2[/tex]
[tex]\frac{f(7)-13}{5}\geq 2[/tex]
[tex]f(7)-13\geq 2\times 5[/tex]
[tex]f(7)-13\geq 10[/tex]
[tex]f(7)\geq 10+13[/tex]
[tex]f(7)\geq 23[/tex]
The small value of f(7) can be 23.
