Given:
The equation of a parabola is:
[tex]y=(x+2)^2-1[/tex]
To find:
The coordinates of the vertex of the given equation.
Solution:
The vertex form of a quadratic function is:
[tex]y=a(x-h)^2+k[/tex] ...(i)
Where, a is a constant and (h,k) is the vertex.
We have,
[tex]y=(x+2)^2-1[/tex] ...(ii)
On comparing (i) and (ii), we get
[tex]a=1[/tex]
[tex]h=-2[/tex]
[tex]k=-1[/tex]
We know that the vertex of the parabola is (h,k).
Therefore, the vertex of the given equation is (-2,-1).
