Answer:
[tex]f^{-1}[/tex](x) = [tex]\frac{x+1}{5}[/tex]
Step-by-step explanation:
let y = f(x) and rearrange making x the subject , that is
y = 5x - 1 ( add 1 to both sides )
y + 1 = 5x ( divide both sides by 5 )
[tex]\frac{y+1}{5}[/tex] = x
Change y back into terms of x , with x = [tex]f^{-1}[/tex] (x) , then
[tex]f^{-1}[/tex] (x) = [tex]\frac{x+1}{5}[/tex]
