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We know, the probability of an event = Favorable outcomes / Total outcomes.
In a case of two dices,
Total outcomes = 6 × 6 = 36
A.T. Q favorable outcome is a sum of 6,
Ways of obtaining a sum of 6
(1,5), (5,1), (2,4),(4,2) and (3,3). Total 5 ways in which 6 can be obtained using two dices.
Therefore, required probability (P),
P = 5/ 36
