natasyashhbanii natasyashhbanii
  • 20-06-2021
  • Mathematics
contestada

The root for an equation x²-px+6=0 ls 3. Find the value of p
Jawapan / Anne
IP​

Respuesta :

omotayoadekoya1 omotayoadekoya1
  • 25-06-2021

Answer:

5

Step-by-step explanation:

Given that 3 is a root of the equation x²-px+6=0

To find the value of p, substitute 3 into the equation for x

Hence x²-px+6=0

becomes

3^2 - 3p + 6 = 0

9 -3p + 6 = 0

collect like terms

-3p = -9 - 6

-3p = -15

Divide both sides by -3

p = -15/-3

p = 5

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