Answer:
x = 8
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, then
The square of the tangent is equal to the product of the secants external part and the whole secant, that is
x² = 4(4 + 12) = 4 × 16 = 64 ( take the square root of both sides )
x = [tex]\sqrt{64}[/tex] = 8
