Answer:
[tex]Step1. Find \ slope \ of \ the \ line \ passing \ through\ P(6,2), Q(8,-4)\\m = \frac{y_{2} -y_{1} }{x_{2}- x_{1} } = \frac{-4-2}{8-6} = \frac{-6}{2} = -3[/tex]
[tex]Step2 . Equation \ of \ line\ \\(y - y_{2}) = m (x -x_{2} )\\ (y + 4) = -3(x - 8)\\y + 4 = -3x +24\\y = -3x +24-4\\y = -3x +20[/tex]
