Answer:
1.06 moles of nitrogen gas will react with 3.20 moles of magnesium in the container.
Explanation:
[tex]3 Mg (s) + 1 N_2 (g) \rightarrow 1 Mg_3N_2 (s)[/tex]
Moles of magnesium heated = 3.20 mol
According to reaction, 3 moles of magnesium reacts with 1 mole of nitrogen gas, then 3.20 moles of magnesium will react with:
[tex]=\frac{1}{3}\times 3.20 mol=1.07 \text{ mol of }N_2[/tex]
1.06 moles of nitrogen gas will react with 3.20 moles of magnesium in the container.
