yolandamurillo yolandamurillo
  • 19-05-2021
  • Mathematics
contestada

NEEED HELP THANK YOU

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Respuesta :

abidemiokin
abidemiokin abidemiokin
  • 24-05-2021

Answer:

z = -1

Step-by-step explanation:

Given the equation;

[tex]\frac{1}{z+1} +\frac{5}{z+5} = \frac{4}{z^2+6z+5}\\[/tex]\

Find the LCM

[tex]\frac{1(z+5)+5(z+1)}{z^2+6x+5} = \frac{4}{z^2+6z+5}\\\\1(z+5)+5(z+1) = 4\\Expand\\z+5+5z+5 = 4\\6z+10 = 4\\6z = 4 -10\\6z = -6\\z = -6/6\\z = -1\\[/tex]

Hence the value of z that satisfies the equation is -1

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