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Suppose you have AB on a coordinate plane located at A(-3, -4) and B(5, -4). Under a dilation centered at (9, 0), AB becomes A'B' with coordinates A'(6, -1) and B'(8, -1). What is the scale factor for this dilation?

Respuesta :

Answer:

My guess is that you would find the distance between points for both AB and A'B'

so it would look something like this

distance formula = [tex]\sqrt{(y2-y1)^2 + (x2-x1)^2} = \sqrt{(5+3)^2 + (-4+4)^2} = 8 =AB distance[/tex]

do the same for A'B'

[tex]\sqrt{(8-6)^2 + (-1+1)^2} = 2 = A'B' distance[/tex]

so the scale factor of the dilation would be 1/4

Step-by-step explanation:

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