Answer:
sin θ = [tex]\frac{7}{8}[/tex]
Step-by-step explanation:
Substitute cos θ = [tex]\frac{\sqrt{15} }{8}[/tex] into the Pythagorean identity
(sin θ )² + ( [tex]\frac{\sqrt{15} }{8}[/tex] )² = 1
(sin θ )² + [tex]\frac{15}{64}[/tex] = 1
(sin θ )² = 1 - [tex]\frac{15}{64}[/tex] = [tex]\frac{49}{64}[/tex] ( take the square root of both sides )
sin θ = [tex]\sqrt{\frac{49}{64} }[/tex] = [tex]\frac{7}{8}[/tex]
