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20-04-2021
Chemistry

contestada

How many grams of calcium carbonate, CaCO3, contain 48 grams of oxygen atoms?

A) 41
B) 50
C) 62
D) 88
E) 100

Respuesta :

HumanoidGamer HumanoidGamer

21-04-2021

Answer:

(40 g O) / (15.99943 g O/mol) x (1 mol CaCO3 / 3 mol O) x (100.0875 g CaCO3/mol) =

83 g CaCO3

So answer D), although three significant digits are not justified.

Your welcome! Please give me brainiest and have a Great day! <3

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