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A traveling circus is moving in a train consisting of 20 cars, which were randomly adjoined to each other. 2 cars are carrying clowns, 2 cars house trapeze artists, 4 are reserved for lions, 4 - for bears, 4 - for elephants, and 4 for tents and provisions. What is the probability that no elephant or bear car precedes the first car with lions

Respuesta :

Answer:

the no elephant or bear car precedes the first car with lions is 0.60

Step-by-step explanation:

The computation of the probability is shown below:

= 1 - (no depend or acrobat car precedes)

=  1 - (4 ÷ 20  + 4 ÷ 20)

= 1 - 8 ÷ 20

= 20 - 8 ÷ 20

= 12 ÷ 20

= 0.60

Hence, the no elephant or bear car precedes the first car with lions is 0.60

The same would be considered and relevant too

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