gabrielgamino17 gabrielgamino17
  • 16-04-2021
  • Chemistry
contestada

What is the specific heat of silicon if the temperature of a 4.11 g sample of silicon
is increased by 3.8 °C when 11.1 J of heat is added?

Respuesta :

Cricetus
Cricetus Cricetus
  • 21-04-2021

Answer:

The right solution is "0.7107 J/g°C".

Explanation:

The given values are:

Mass,

m = 4.11 g

Temperature,

ΔT = 3.8°C

Heat,

Q = 11.1 J

The specific heat of silicon will be:

⇒  [tex]C=\frac{Q}{m \Delta T}[/tex]

On substituting the values, we get

⇒      [tex]=\frac{11.1}{4.11\times 3.8}[/tex]

⇒      [tex]=\frac{11.1}{15.618}[/tex]

⇒      [tex]=0.7107 \ J/g^{\circ}C[/tex]

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