W3arrMsanch7icki W3arrMsanch7icki
  • 19-11-2016
  • Computers and Technology
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The sequence < un > is defined by the recurrence Un+1 = 3Un+1\5Un+3 initial condition of u1 = 1: Need to show un in terms of Fibonacci / Lucas numbers

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Аноним Аноним
  • 30-11-2016
Sorry but your notation is ambiguous 

Is it U(n+1) = (3U(n) + 1)/(5U(n) + 3) 

or U(n+1) = (3U(n) + 1)/(5U(n)) + 3 

or U(n+1) = 3U(n) + (1/5U(n)) + 3 

or U(n+1) = 3U(n) + (1/5)U(n) + 3? 

If so, what do you wish us to do with this sequence?

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