all2eGoonmeloucholl all2eGoonmeloucholl

19-11-2016
Mathematics

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find the limit. lim (x-5)/((x^2)-25) x-> 5+

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HomertheGenius HomertheGenius

20-11-2016

[tex] \lim_{x \to 5} \frac{x-5}{ x^{2} -25} =( \frac{0}{0} ) = \\ =\lim_{x \to 5} \frac{x-5}{(x-5)(x+5)}= \\ =\lim_{x \to 5} \frac{1}{x+5}= \\ = \frac{1}{5+5}= \frac{1}{10} [/tex] = 0.1

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