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A certain metal M forms a soluble nitrate salt M(NO3), Suppose the left half cell ofa galvanic cell apparatus is filled with a 4.00 M solution of M (NO,), and the right half cell with a 20.0 mM solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 35.0 °C.

Required:
a. Which electrode will be positive?
b. What voltage will the voltmeter show?

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Answer:

Explanation:

The left electrode will be positive on the grounds that focus on the concentration that the cell electron moves from a lower concentration fixation to a higher concentration. Thus right electrode will go about and act as an anode and will be negative.  Also, the left electrode will be the cathode and will be positive.

The concentration cell [tex]E_{Cell} = \dfrac{-0.0591}{1} log \dfrac{0.02}{4}[/tex]

[tex]E_{Cell} =0.136 V[/tex]

         = 136 mV

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