gwynnejunk61 gwynnejunk61
  • 19-03-2021
  • Mathematics
contestada

SOMEONE PLEASE HELP IM FAILING THIS CLASS
Given the similar triangles, find the value of x.
AABC~AAGF

SOMEONE PLEASE HELP IM FAILING THIS CLASS Given the similar triangles find the value of x AABCAAGF class=

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akposevictor
akposevictor akposevictor
  • 24-03-2021

Answer:

x = 4

Step-by-step explanation:

Given that ∆ABC ~ ∆AGF, it follows that their lengths would be proportional to each other. This implies that:

AB/AG = AC/A F

Substitute

55/22 = 30/(4x - 4)

5/2 = 30/(4x - 4)

Cross multiply

5(4x - 4) = 30(2)

20x - 20 = 60

20x - 20 + 20 = 60 + 20

20x = 80

Divide both sides by 20

20x/20 = 80/20

x = 4

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