Answer:
See below
Step-by-step explanation:
For seg FG to be tangent to the circle with center E, the side lengths 6, 10, 12 must follow the rule of Pythagorean triplets.
So,
[tex] {10}^{2} + {6}^{2} = 100 + 36 = 136 \\ \\ {12}^{2} = 144 \\ \\ \because \: {10}^{2} + {6}^{2} \neq \: {12}^{2} \\ [/tex]
From above it is obvious that given segment lengths doesn't follow the Pythagorean triplet rule. Therefore, seg FG is not tangent to the circle with center E.
