Answer:
71° F
Step-by-step explanation:
Consider the rational part of f(t)
[tex]\frac{40t^3}{t^3+100}[/tex] ( divide numerator and denominator by t³
= [tex]\frac{40}{1+\frac{100}{t^3} }[/tex]
As t → infinity then [tex]\frac{100}{t^3}[/tex] → 0 , the expression simplifies to
[tex]\frac{40}{1+0}[/tex] = [tex]\frac{40}{1}[/tex] = 40
Thus after driving for a long time
f(t) = 31 + 40 = 71° F
