tessamathhelp3866 tessamathhelp3866
  • 19-02-2021
  • Mathematics
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The polynomial ax2 − 64 is a difference of two squares. Find all possible values of a between 1 and 100 inclusive. The inclusive values are

Respuesta :

MrRoyal
MrRoyal MrRoyal
  • 23-02-2021

Answer:

[tex]a = \{1,4,9,16,25,36,49,64,81,100\}[/tex]

Step-by-step explanation:

Given

[tex]ax^2 - 64[/tex]

Required

Determine possible values of a

For the expression to be a difference of two squares, then a must be a perfect square between 1 and 100 (inclusive).

Let [tex]a = k^2[/tex] where [tex]k \ge 1[/tex]

When k = 1

[tex]a = 1^2 = 1[/tex]

k = 2

[tex]a = 2^2 = 4[/tex]

k=3

[tex]a = 3^2 = 9[/tex]

It goes on until k = 10

[tex]a = 10^2 = 100[/tex]

So, the possible values of a are:

[tex]a = \{1,4,9,16,25,36,49,64,81,100\}[/tex]

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