kyashe
kyashe kyashe
  • 19-02-2021
  • Mathematics
contestada

I DONT KNOW HOW TO DO THIS HELP MEH
Solve the system by substitution.
3x-8y=-50
6y+=x

Respuesta :

oakaydn1124
oakaydn1124 oakaydn1124
  • 19-02-2021

Answer:

substitution method is tricky until u get the hang of it. 6y=x so 3x-8y=-50 can be rewritten as 3(6y)-8y=-50.

Step-by-step explanation:

3x-8y=-50.........(1)

6y= x ..............(2)

Substituting x = 6y in (1)

3(6y) - 8y = -50

multiply 3(6y)

18y - 8y = -50

subtract 8y from 18y

10y = -50

divide to get y alone

y = -50/10

y = -5

now substitute. you know what y is. 6y=x / 6(-5)=x

solve :)

6y = x

6(-5) = x

-30 = x

x = -30

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