tiagoferreira1000000 tiagoferreira1000000
  • 18-02-2021
  • Chemistry
contestada

calculate the volume occupied by 10g of propane gas, under normal conditions of temperature and pressure

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maacastrobr
maacastrobr maacastrobr
  • 23-02-2021

Answer:

5.5 L

Explanation:

First we convert 10 g of propane gas (C₃H₈) to moles, using its molar mass:

  • 10 g ÷ 44 g/mol = 0.23 mol

Then we use the PV=nRT formula, where:

  • P = 1 atm & T = 293 K (This are normal conditions of T and P)
  • n = 0.23 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • V = ?

1 atm * V = 0.23 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 293 K

  • V = 5.5 L
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