Answer:
Zeros → (-2, 0) and (4, 0)
Step-by-step explanation:
Equation of the graph has been given as,
y = [tex]\frac{1}{2}x^{2} -x-4[/tex]
For zeros of the function,
y = 0
Therefore, [tex]\frac{1}{2}x^{2} -x-4=0[/tex]
By solving the equation algebraically,
x² - 2x - 8 = 0
x² - 4x + 2x - 8 = 0
x(x - 4) + 2(x - 4) = 0
(x + 2)(x - 4) = 0
x = -2, 4
Therefore, coordinates of the zeros will be (-2, 0) and (4, 0).
Let's confirm the zeros (x-intercepts) from the graph attached,
Coordinates of the x-intercepts are,
(-2, 0) and (4, 0)
