Answer:
The induced emf in the coil is 2.88 V
Explanation:
Given;
number of turns of the coil, N = 40
cross sectional area of the coil, A = 12.0 cm² = 12 x 10 ⁻⁴ m²
the magnetic field strength, B = 1.2 T
change in time, dt = 20 ms = 20 x 10⁻³ s
The emf induced in the coil is calculated as;
[tex]emf = -N\frac{d\phi }{dt} \\\\emf = N (\frac{BA}{dt} )\\\\emf = \frac{40 \ \times \ 1.2 \ \times \ 12\times 10^{-4}}{20 \times 10^{-3}} \\\\emf = 2.88 \ V[/tex]
Therefore, the induced emf in the coil is 2.88 V
