Answer:
y = 2[tex]\sqrt{5}[/tex], if you plug into expressions for angles K and J they equal 80°
Step-by-step explanation:
from notations given it appears that ΔFKH is similar to ΔIJG, which means their angles are congruent
therefore, we can say that 4y² = 6y² - 40
-2y² = -40
y² = 20
y = √20 or 2√5
to find the measure in degrees, plug 2√5 into each expression:
4 · (2√5)² = 4 · 4 ·5 = 80°
6 · (2√5)² = (6 · 4 ·5) - 40 = 80°
