cmandeployedjr cmandeployedjr
  • 18-12-2020
  • Mathematics
contestada

Sequences and series

Sequences and series class=

Respuesta :

surjithayer10 surjithayer10
  • 24-12-2020

Answer:

D

Step-by-step explanation:

[tex]a_{n}=\frac{(n+3)!}{(n+3}=\frac{(n+3)(n+2)!}{n+3}=(n+2)!\\a_{1}=(1+2)!=3!=3*2*1=6\\a_{2}=(2+2)!=4!=4*3*2*1=24\\a_{3}=(3+2)=5!=5*4!=5*24=120\\a_{4}=(4=2)!=6!=6*5!=120*6=720\\a_{5}=(5+2)=7!=7*6!=720*7=5040[/tex]

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