Answer: 2x+y+11=0
Step-by-step explanation:
The equation of given line is x-2y-2=0
Slope of given line is (m1)= - coefficient of x÷coefficient of y
m1= -1÷-2 =1÷2
Let slope of required line be m2.
Since the two lines are perpendicular,
So,
m1×m2= -1
or, 1÷2×m2 = -1
m2 = -2
The required line is passing through (4,-3)
Using two points slope form,
y-y1 = m(x-x1)
or, y-(-3)= -2(x+4)
or, y+3= -2x -8
or, 2x+y+3+8 = 0
2x+y+11 = 0 which is required equation of line.
