Answer:
68.42%
Step-by-step explanation:
We need to find the percent of Cr in [tex]Cr_2O_3[/tex].
Mass of Cr = 52 amu
Mass of O = 16 amu
Firstly, we will find the molar mass of [tex]Cr_2O_3[/tex] as follows :
M = 2(52) + 3(16)
M = 152 amu
Percent of Cr in [tex]Cr_2O_3[/tex] will be :
[tex]Cr=\dfrac{2\times 52}{152}\times 100\\\\=68.42\%[/tex]
Hence, the required percentage is 68.42%.
