Answer: [tex]f(n) =f(1)+0.2(n-1)[/tex]
Step-by-step explanation:
Given: [tex]a_n=5+0.2(n-1)[/tex]
It is the formula of nth term [tex][a_n=a+(n-1)d][/tex] in Arithmetic progression
where 5 = First term
0.2 = common difference
To write first term , we use f(1).
nth term will be
[tex]f(n) =f(1)+0.2(n-1)[/tex]
Hence, the function form : [tex]f(n) =f(1)+0.2(n-1)[/tex]
