Respuesta :

Answer: 154.09 g

Explanation:

3 Mg + 2 FeCl3 = 3 MgCl2 + 2 Fe

The mass of MgCl2 produced is calculated:

m MgCl2 = 175 g FeCl3 * (1 mol FeCl3 / 162.2 g) * (3 mol MgCl2 / 2 mol FeCl3) * (95.21 g MgCl2 / 1 mol) = 154.09 g