Answer:
15.0 g
Explanation:
Step 1: Given and required data
- Heat used to melt a sample of ice (Q): 5.01 kJ
- Latent heat of fusion of water (ΔH°fus): 334 kJ/kg
Step 2: Calculate the mass (m) of water
334 kJ are required to melt 1 kg of ice at 0°C (melting point of water). We can calculate the mass of ice melted by 5.01 kJ using the following expression.
Q = ΔH°fus × m
m = Q / ΔH°fus
m = 5.01 kJ / (334 kJ/kg)
m = 0.0150 kg = 15.0 g
