docbeaver16 docbeaver16
  • 16-11-2020
  • Mathematics
contestada

What is the vertex of (x) = –16x² + 64x + 80.

Respuesta :

unicorn3125
unicorn3125 unicorn3125
  • 17-11-2020

Answer:

           (2, 124)

Step-by-step explanation:

f(x) = a(x - h)² + k      - the  vertex form of the equation of the parabola with vertex (h, k)

[tex]f(x) = -16x^2+ 64x + 80\\\\f(x) = -16(x^2- 4x) + 80\\\\f(x) = -16(\underline {x^2-2\cdot2x\cdot2+2^2}-2^2) + 80\\\\f(x) = -16\big[(x-2)^2-4\big] + 80\\\\f(x) = -16(x-2)^2+64 + 80\\\\\bold{f(x)=-16(x-2)^2+124\quad\implies\quad h=2\,,\quad k=124}[/tex]

The vertex is (2, 124)

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