Answer:
Step-by-step explanation:
If -3/2 and 5 are solutions to the quadratic equation, hence the expression will give;
(x-(-3/2))(x-5) = 0
(x+3/2)(x-5) = 0
Compare the resulting expression with (ax+b)(x+c)=0, we can see that;
ax = x
divide both sides by x
ax/x = x/x
a = 1
b = 3/2
-5 = +c
c = -5
Hence a = 1, = 3/2 and c = -5
