shadiashediz shadiashediz
  • 16-11-2020
  • Mathematics
contestada

(2x+3y=23)(3x+4y=15)using ellimination method.

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Respuesta :

tasni109
tasni109 tasni109
  • 16-11-2020

Answer:

x = -47, y = 39

Step-by-step explanation:

2x+3y=23 →equation 1

3x+4y=15 →equation 2

by elimination method,

(2x+3y=23) × 4

(3x+4y=15) × 3

8x + 12y = 92

(-)      (-)       (-)

9x + 12y = 45

---------------------

-1x + 0    = 47

-x = 47

x = -47

substitute x=-47 in equation 1

2(-47) + 3y = 23

-94 + 3y = 23

3y = 23 + 94

3y = 117

y = 117/3

y = 39

therefore, x = -47 and y = 39

hope you understood ❤❤❤

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