jp240553 jp240553
  • 16-11-2020
  • Mathematics
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factoring. 2n^2+4n+2=0

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Respuesta :

Adityax26 Adityax26
  • 16-11-2020
2n^2 + 4n + 2 = 0
Divide both sides by 2:
n^2 + 2n + 1 = 0
Find two numbers that multiply to form C (1) and add together to form 2: these numbers are 1 and 1:
(n +1)(n+1) = 0
(n+1)^2 = 0
Therefore n+1 = 0
n = -1
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