atticus42 atticus42

21-10-2020
Chemistry

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What mass of calcium bromide is needed to prepare 150.0 mL of a 3.50 M solution? (Assume that the molecular weight of CaBr2 is 200.618 g/mol)

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zacharynguyen07 zacharynguyen07

24-10-2020

Answer:

105g

Use the following formula to calculate the mass of calcium bromide that is needed:

volume of solution × molar concentration × molar mass = mass of solute

The result is 105 g, which has three significant figures, because the term with the least precision (3.50 M) has three significant figures.

Explanation:

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