fireblast929
fireblast929 fireblast929
  • 20-10-2020
  • Mathematics
contestada

Find the vertex of the function given below


[tex]y = {x}^{2} - 6x + 1[/tex]
​

Respuesta :

730001624
730001624 730001624
  • 20-10-2020

Answer:

3,-10...........................

Answer Link
jimrgrant1 jimrgrant1
  • 20-10-2020

Answer:

vertex = (3, - 8 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]

y = x² - 6x + 1 ← is in standard form

with a = 1 and b = - 6 , thus

[tex]x_{vertex}[/tex] = - [tex]\frac{-6}{2}[/tex] = 3

Substitute x = 3 into the function for y

y = 3² - 6(3) + 1 = 9 - 18 + 1 = - 8

vertex = (3, - 8 )

Answer Link

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