christianyaku christianyaku
  • 18-10-2020
  • Mathematics
contestada

Solve for x and y in the equation.
xy=80 and log x - 2 log y =1

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sqdancefan
sqdancefan sqdancefan
  • 18-10-2020

9514 1404 393

Answer:

  (x, y) = (40, 2)

Step-by-step explanation:

Taking the antilog of the second equation, we have ...

  x/y^2 = 10

  x = 10y^2

Substituting this into the first equation gives ...

  (10y^2)y = 80

  y^3 = 8 . . . . . . . . divide by 10

  y = 2 . . . . . . . . . . cube root

  x = 10·2^2 = 40

The solution is (x, y) = (40, 2).

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