Answer:
f = 0
No solution
Step-by-step explanation:
[tex] \frac{1}{3} (12f - 3) = 4f - 1[/tex]
Use ⅓ to open the bracket
[tex] \frac{1}{3} \times \: 12f = 4f \\ \frac{1}{3} \times 3= 1[/tex]
[tex]4f - 1= 4f - 1[/tex]
Collect like terms
[tex]4f - 4f = - 1+1 \\ - 1f = 0 \\ \\ f = 0[/tex]
