The equation is x+(x+2)+(x+4)=126, and the greatest consecutive integers is 44.
Explanation:
If x is the smallest consecutive integer, the next even integer up would be (x+2), and the next one up from that would be (x+2+2)=(x+4).
Their sum is 126, so x+(x+2)+(x+4)=126.
Combine like terms and we have 3x+6=126.
Subtract 6 from both sides:
3x+6-6=126-6
3x=120.
Divide both sides by 3:
3x/3 = 120/3
x=40.
This makes the least consecutive integer 40. The next one up would be 40+2=42, and the greatest would be 40+4=44.
