kalsoomshafqat kalsoomshafqat

18-09-2016
Mathematics

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the zeros of the function f(x)=3x^2-3x-6 are

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dalendrk dalendrk

18-09-2016

f(x) = 3x² - 3x - 6

The zeros f(x) = 0 ⇒ 3x² - 3x - 6 = 0

3x² - 6x + 3x - 6 = 0

3x(x - 2) + 3(x - 2) = 0

(x - 2)(3x + 3) = 0 ⇔ x - 2 = 0 ∨ 3x + 3 = 0

x = 2 ∨ 3x = -3

x = 2 ∨ x = -1

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