Answer:
[tex]a=\dfrac{3b-7}{3}[/tex]
Step-by-step explanation:
Given that,
The given equation is :
5b + 6a – 7 = 2b + 9a
We need to solve the above equation for a. Taking he terms having a and b in LHS and constants in RHS.
5b+6a-2b-9a=7
taking like terms together
(6a-9a)+(5b-2b)=7
-3a+3b=7
Subtracting both sides by 3b. So,
-3a+3b-3b=7-3b
-3a=7-3b
Dioviding both sides by (-3). So,
[tex]a=\dfrac{7-3b}{-3}\\\\a=\dfrac{3b-7}{3}[/tex]
Hence, the value of a is [tex]a=\dfrac{3b-7}{3}[/tex].
