cristie68
cristie68 cristie68
  • 17-09-2020
  • Mathematics
contestada

someone knows this one? help me please help help :(
thank you so much​

someone knows this one help me please help help thank you so much class=

Respuesta :

tramserran
tramserran tramserran
  • 17-09-2020

Answer:  d

Step-by-step explanation:

[tex]KE=\dfrac{1}{2}mv^2\\\\\\\bigg(\dfrac{2}{m}\bigg)KE=\bigg(\dfrac{2}{m}\bigg)\dfrac{1}{2}mv^2\\\\\\\bigg(\dfrac{2}{m}\bigg)KE=v^2\\\\\\\sqrt{\bigg(\dfrac{2}{m}\bigg)KE}=\sqrt{v^2}\\\\\\\sqrt{\bigg(\dfrac{2}{m}\bigg)KE}=v[/tex]

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